This is the same as probability of 2, 3, 4 or 5 dinners being selected.
P(2) = 5/13 * 4/12 * 8/11 * 7/10 * 6/9 = ?
P(5) = 5/13 * 4/12 * 3/11 * 2/10 * 1/9 = ?
Probability of P(2), P(3), P(4) or P(5) = sum of these probabilities.
Assume that there are 13 frozen dinners: 5 pasta, 4 chicken, and 4 seafood dinners. The student selects 5 of them.
What is the probability that at least 2 of the dinners selected are pasta dinners?
1 answer
1 answer