To find the value of \( c \) such that \( P(Z > c) = 0.1734 \), we first need to determine the corresponding z-score for the cumulative probability. This can be done more easily by using the complement:
\[ P(Z \leq c) = 1 - P(Z > c) = 1 - 0.1734 = 0.8266 \]
Now we need to find the z-score that corresponds to a cumulative probability of 0.8266.
Using a standard normal distribution table or a calculator, we look for the z-score that yields an area of 0.8266 to its left. The z-score that corresponds to this cumulative probability is approximately:
\[ z \approx 0.95 \]
Now, we can conclude that:
\[ c \approx 0.95 , °C \]
Thus, the reading that separates the highest 17.34% from the rest is:
\[ c = 0.95 , °C \]