at least one boy ----> exclude the case of all 5 girls, which is (1/2)^5 = 1/32
prob(at least one boy in 5) = 1 - 1/32
= 31/32
Assume that the probability of a boy being born is the same as the probability of a girl being born. Find the probability that a family with five children will have at least one boy.
1, 4/5, 13/16, 1/32, 31/32
Can someone please explain?
Thank you
1 answer
1 answer