C is in hundred so divide by 100
substitute in C = 5250 and solve for x
substitute in C = 7810 and solve for x
Assume that the mathematical model C(x) = 16x + 130 represents the cost C, in hundreds of dollars, for a certain manufacturer to produce x items. How many items x can be manufactured while keeping costs between $525,000 and $781,000? Thanks in advance!
3 answers
C(x) =16x+130 {x| 320 < x <480
525,000/100
5,250=16x+130
16x=5,250-130
16x=5,120
x=5,120/16
x=320
781,000/100
7,810=16x+130
16x=7,810-130
16x=7,680
x=7,680/16
x=480
Then if that is true then this is the solution? I think I got it!
525,000/100
5,250=16x+130
16x=5,250-130
16x=5,120
x=5,120/16
x=320
781,000/100
7,810=16x+130
16x=7,810-130
16x=7,680
x=7,680/16
x=480
Then if that is true then this is the solution? I think I got it!
so anything between those numbers 320 and 480 if you did the arithmetic right