The sum of the angles in a triangle is 180 degrees, so we have:
m<P + m<Q + m<O = 180
28 + 90 + m<O = 180
m<O = 62 degrees
Therefore, the value of x is 62 degrees.
Assume that lines that appear to be tangent are tangent. Point O is the center of the circle. PQO is a right triangle. Find the value of x if the m<P = 28 (1 point) Responses 66 degrees 66 degrees 68 degrees 68 degrees 64 degrees 64 degrees 62 degrees
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