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suppose it takes a college student an average of 5 minutes to find a parking space on the schools parking lot. Assume also that...Asked by Anonymous
Assume that it takes a college student an average of 5 minutes to find a parking spot in the main parking lot. Assume also that this time is normally distributed with a standard deviation of 2 minutes. What time is exceeded by approximately 75% of the college students when trying to find a parking spot in the main parking lot?
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Answered by
Steve
Look up 0.7500 in your Z table. That is -.674 std from the mean.
Now scale and shift it for your problem:
5 - .675(2) = 3.65
A handy place to play around with this stuff is
http://davidmlane.com/hyperstat/z_table.html
Now scale and shift it for your problem:
5 - .675(2) = 3.65
A handy place to play around with this stuff is
http://davidmlane.com/hyperstat/z_table.html
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