Assume an organic compound has a partition coefficient between water and diethyl ether equal to 7.33. If there are initially 9.81 grams of the compound dissolved in 100.0 mL of water, how many grams will remain in the aqueous layer after extraction with one 30.0 mL portion of ether?
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The usual way of expressing this is as organic/aqueous layer. I will assume that is the 7.33 value. Ko/a = 7.33.
7.33 = (concn organic layer)/(concn aq layer)
Let x = grams in organic layer, then 9.81-x = grams in aq layer.
7.33 = (x/30)/(9.81-x)/100
Solve for x and 9.81-x
7.33 = (concn organic layer)/(concn aq layer)
Let x = grams in organic layer, then 9.81-x = grams in aq layer.
7.33 = (x/30)/(9.81-x)/100
Solve for x and 9.81-x
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