for the complementary angle property
sinA = cos(90-A)
so
cos(2A+40) = sin(3A-60)
sin(90 - (2A+40) ) = sin(3A-60)
sin(50-2A) = sin(3A-60)
then
50-2A = 3A-60
110 = 5A
A = 22°
assume A= alpha
using complementary rule how do I solve for alpha?
cos(2A+40) =sin(3A-60)
I don't understand how to start the question. What are the steps in solving for alpha.
Do i get cos to equal sin somehow?
1 answer
1 answer