and this one please <3
As x → 0−, sin x →?
As x → (π/4), sin x → ?
As x → π, cos x → ?
As x → (π/3)^+, cos x → ?
2 answers
well, you know that
cos π = -1
cos π/3 = 1/2
sin 0 = 0
sin π/4 = 1/√2
Since all these function are continuous everywhere, the limits from both sides exist, and are the same. Namely, the function value there.
cos π = -1
cos π/3 = 1/2
sin 0 = 0
sin π/4 = 1/√2
Since all these function are continuous everywhere, the limits from both sides exist, and are the same. Namely, the function value there.