To understand the outcome when using a 700-gram car instead of a 500-gram car, we need to consider the concepts of potential energy (PE) and kinetic energy (KE).
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Potential Energy (PE): The potential energy at a height (point X) is given by the formula \( PE = mgh \), where \( m \) is the mass (in kg), \( g \) is the acceleration due to gravity (approximately 9.8 m/s²), and \( h \) is the height (in meters) at which the car is placed. Since the 700-gram car is heavier than the 500-gram car, it will have more potential energy at the same height, barring any changes in height.
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Kinetic Energy (KE): The kinetic energy at the bottom of the racetrack can be calculated by the formula \( KE = \frac{1}{2} mv^2 \). As the car rolls down the track, the potential energy converts into kinetic energy. Therefore, if potential energy is greater (which it will be for the 700-gram car), the kinetic energy at the bottom will also be greater (assuming no energy losses).
Based on this information:
- Potential Energy: The 700-gram car would have more potential energy at point X compared to the 500-gram car.
- Kinetic Energy: As it rolls down, it would also have more kinetic energy at the bottom compared to the 500-gram car.
Thus, the most likely outcome from using a 700-gram car instead of a 500-gram car is:
A 700-gram car would have more potential energy at point X and more kinetic energy at the bottom of the racetrack.