as she pick up her riders a bus driver traverses four successive displacements represented by the expression (-6.30 b)i-(4.00 b cos 40)i-(4.00 sin 40)j+(3.00 b cos 50)i-(3.00 b sin 50)j-(5.00 b)j here b represents one city block,a convenient unit of distance of uniform size; i is east; and j is north. the displacements at 40 degree and 50 degree represent travel on roadways in the city that are at these angles to the main east-west and north-south streets.(a)draw a map of the successive displacements(b)what total distance did she travel? (c)compute the magnitude and direction of her total displacements.
5 answers
PLEASE ANSWERS MY ASSIGNMENT
If I read your somewhat confusing vectors correctly, they are (in units of b)
-6.30i
-4.00cos40i - 4.00sin40j
3.00cos50i - 3.00sin50j
-5.00j
the distances traveled in each case is
6.30
4.00
3.00
5.00
adding up to 18.30
the directions are all given. just read 'em off
-6.30i
-4.00cos40i - 4.00sin40j
3.00cos50i - 3.00sin50j
-5.00j
the distances traveled in each case is
6.30
4.00
3.00
5.00
adding up to 18.30
the directions are all given. just read 'em off
what the answer to letter c. how can i find the answer please illustrate to me
adding up the i and j values, the total displacement is
-12.4i - 4.87j = 13.32 @ 158.6°
|-12.4i - 4.87j| = √(12.4^2 + 4.87^2)
tan158.6° = -4.87/-12.4
-12.4i - 4.87j = 13.32 @ 158.6°
|-12.4i - 4.87j| = √(12.4^2 + 4.87^2)
tan158.6° = -4.87/-12.4
how did u get -12.4i and 4.87j
3 answers