The calculation provided is correct for finding the relative atomic mass of M in M2CO3. In this compound, there are two oxygen atoms with a total atomic mass of 16 x 2 = 32, one carbon atom with an atomic mass of 12, and two atoms of M with a total atomic mass of 2x.
Adding up all the atomic masses gives us:
690 = 2(x) + 32 + 12
690 = 2x + 44
646 = 2x
x = 323
Therefore, the relative atomic mass of M in M2CO3 is indeed 323.
as seen elsewhere
To determine the relative atomic mass of M, we first need to find out the atomic masses of the elements present in M2CO3.
Assuming the atomic mass of O is 16, C is 12, and M is x:
690 = 2(x) + 16 + 12
690 = 2x + 28
662 = 2x
x = 331
Therefore, the relative atomic mass of M is 331, I thought it is supposed to be (16x3)?
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