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As Isla prepares to set off fireworks, she wants to ensure the spectators are a safe distance away. When shot in the air, one f...Asked by hiiiii
As Isla prepares to set off fireworks, she wants to ensure the spectators are a safe distance away. When shot in the air, one firework will follow the path h(x)=−x2+15x
, where h(x) is the height of the firework, and x is the horizontal distance it travels in feet. To determine how far the firework will travel before it reaches the ground, Isla sets the height equal to zero, and solves the following quadratic equation: 0=−x2+15x
. How far will the firework travel before it reaches the ground?(1 point)
Responses
15 feet
15 feet
30 feet
30 feet
7.5 feet
7.5 feet
−15
feet
, where h(x) is the height of the firework, and x is the horizontal distance it travels in feet. To determine how far the firework will travel before it reaches the ground, Isla sets the height equal to zero, and solves the following quadratic equation: 0=−x2+15x
. How far will the firework travel before it reaches the ground?(1 point)
Responses
15 feet
15 feet
30 feet
30 feet
7.5 feet
7.5 feet
−15
feet
Answers
Answered by
GPT-4o mini
To determine how far the firework will travel before it reaches the ground, we need to solve the equation \(0 = -x^2 + 15x\).
We can rewrite this as:
\[
-x^2 + 15x = 0
\]
Factoring the equation gives us:
\[
x(-x + 15) = 0
\]
Setting each factor to zero, we get:
1. \(x = 0\) (this represents the starting point)
2. \(-x + 15 = 0\) which simplifies to \(x = 15\)
Thus, the firework will reach the ground at \(x = 15\) feet.
The answer is **15 feet**.
We can rewrite this as:
\[
-x^2 + 15x = 0
\]
Factoring the equation gives us:
\[
x(-x + 15) = 0
\]
Setting each factor to zero, we get:
1. \(x = 0\) (this represents the starting point)
2. \(-x + 15 = 0\) which simplifies to \(x = 15\)
Thus, the firework will reach the ground at \(x = 15\) feet.
The answer is **15 feet**.
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