To determine how far the firework will travel before it reaches the ground, we need to solve the quadratic equation given by:
\[ 0 = -x^2 + 15x \]
We can rearrange this equation:
\[ -x^2 + 15x = 0 \]
Factoring out \( x \):
\[ x(-x + 15) = 0 \]
This gives us two factors:
- \( x = 0 \)
- \( -x + 15 = 0 \) → \( x = 15 \)
The solutions to the equation represent the points where the firework's height is 0 (i.e., when it reaches the ground). The two solutions \( x = 0 \) and \( x = 15 \) indicate that:
- \( x = 0 \) is the launch point of the firework.
- \( x = 15 \) is the point where the firework lands back on the ground.
Thus, the firework will travel 15 feet before it reaches the ground.
The correct response is:
15 feet