Let x be the altitude gain in thousands of feet. The temperature change is then -3.6x°F. The temperature at cruising altitude is -43°F. Setting up the equation, we get:
65 - 3.6x = -43
Adding 3.6x to both sides:
65 = -43 + 3.6x
Adding 43 to both sides:
108 = 3.6x
Dividing both sides by 3.6:
x = 30
Therefore, the plane is at an altitude of 30,000 feet.
As an airplane rises, the outside temperature drops 3.6°F for each 1000 feet of elevation gain. Suppose the outside temperature is 65°F on the ground when the plane takes off and -43°F at cruising altitude. How high is the plane then? Algebra
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