As a train accelerates from a station, it reaches a speed of 4.7m/s in 5.0s. If a train acceleration remains constant what is its speed after an additional 6.0s has elapsed?

Answer 1

You will have to assume that it started at speed = 0 at t = 0. The acceleration rate is therefore
a = 4.7/5.0 = 0.94 m/s^2

After 6.0 MORE seconds at the same acceleration rate, the speed will be
0.94 * 11 = 10.34 m/s

11 seconds is the total time from the start of motion.

Answer 2

drwls, so where did the 11 come from that you multiplied with 0.94?

Answer 3

six seconds is added to the original five seconds, time =11s