As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. A record Chinook salmon has a length of 1.50 m and a mass of 49.5 kg. If this fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 5.60 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine the following.
(a) the salmon's acceleration?
(b) the magnitude of the force F during this interval?
3 answers
I know for the second part i have to do F(Total) = m( a + g). But i don't know how to solve for the accelaration
the average speed over the interval is (3.00 m/s + 5.60 m/s) / 2 = 4.30 m/s
2/3 of its length is 1.00 m
so the time of the interval is
... 1.00 m / 4.30 m/s
the change in speed is
... 5.30 m/s - 3.00 m/s
acceleration is ... speed change / time
2/3 of its length is 1.00 m
so the time of the interval is
... 1.00 m / 4.30 m/s
the change in speed is
... 5.30 m/s - 3.00 m/s
acceleration is ... speed change / time
Okay so I solved for it then plugged my answer (11.3) into the second equation and got 1044. Thank you!