As a baseball is being caught, it's speed goes from 30.0m/s to 0m/s in about 0.0050s. The mass of the baseball is 0.145kg

A) what is the baseballs acceleration
B) what are the magnitude and direction of the force acting on it?
C) what is the magnitude and direction of the force acting on the player who caught it?

2 answers

A. a=(V-Vo)/t = (0-30)/0.005=-6000 m/s^2

B. F = m*a = 0.145 * (-6000) = -870 N.
4432