- Which equation written in standard form represents the number of tickets bought, t, and the number of buckets of popcorn bought, p?
To formulate the correct equation, let's set \( t \) as the number of tickets and \( p \) as the number of popcorn buckets. The cost of tickets is \( 12t \) and the cost of popcorn is \( 7p \). The total spending is \( 62 \). Therefore, the equation can be stated as: \[ 12t + 7p = 62 \]
So the answer is: 7p + 12t = 62.
- What is the equation of the graphed line written in standard form?
For a vertical line passing through x = -3, the equation is simply: \[ x = -3 \]
So the answer is: x = -3.
- What is the x-intercept of the graph of the equation x + 2y = 5?
To find the x-intercept of the equation \( x + 2y = 5 \), set \( y = 0 \): \[ x + 2(0) = 5 \Rightarrow x = 5. \]
So the answer is: 5.
- What is the equation of the graphed line passing through (-3, 0), (0, -2), and (3, -4) written in standard form?
First, find the slope using any two points (let’s use (-3, 0) and (0, -2)): Slope \( m = \frac{-2 - 0}{0 - (-3)} = \frac{-2}{3}. \)
Using point-slope form \( y - y_1 = m(x - x_1) \), we can use point (0, -2): \[ y + 2 = -\frac{2}{3}x \] Multiply by 3 to eliminate fractions: \[ 3y + 6 = -2x \] Rearranging gives us: \[ 2x + 3y = -6. \]
So the answer is: 2x + 3y = -6.
- Which is the equation of the graphed line written in standard form passing through (-4, -4), (0, 0), and (4, 4)?
The points (0, 0) show it's the origin. The slope between these points is 1 (therefore the line is y = x). In standard form, this can be rearranged to: \[ x - y = 0. \]
So the answer is: y = x.
- What is the slope of the line 4x - 2y = 5?
To find the slope, we can rearrange the equation to slope-intercept form (\(y = mx + b\)): \[ -2y = -4x + 5 \] \[ y = 2x - \frac{5}{2} \] The slope \( m \) is \( 2 \).
So the answer is: 2.
- What is the equation of the graphed line passing through (0, -4) and (2, 0) written in standard form?
The slope using the two points is given by \( m = \frac{0 - (-4)}{2 - 0} = \frac{4}{2} = 2 \). Using point-slope form at point (0, -4): \[ y + 4 = 2(x - 0) \] Multiply to get: \[ y = 2x - 4 \] Rearranged to standard form gives: \[ 2x - y = 4. \]
So the answer is: 2x - y = 4.
- What is the x-intercept of the curve described by the equation 2x - 3y = 12?
To find the x-intercept, set \( y = 0 \): \[ 2x - 3(0) = 12 \] \[ 2x = 12 \Rightarrow x = 6. \]
So the answer is: 6.
- What is the slope of the line 3x - 9y = 4?
Rearranging to slope-intercept form: \[ -9y = -3x + 4 \] Divide by -9: \[ y = \frac{1}{3}x - \frac{4}{9} \] So the slope \( m = \frac{1}{3} \).
So the answer is: StartFraction one-third EndFraction.
- What is the graph of 3x + 5y = -15?
To find the intercepts:
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x-intercept: Set \( y = 0 \): \[ 3x = -15 \Rightarrow x = -5. \]
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y-intercept: Set \( x = 0 \): \[ 5y = -15 \Rightarrow y = -3. \]
Therefore, the graph passes through (-5, 0) and (0, -3). So the answer is: A coordinate plane with a line passing through (negative 5, 0) and (0, negative 3).