Arrange these following compounds: Diethyl ether, sec- Butyl alcohol and pentane according to their expected boiling points, with the lowest boiling point first and explain your answer

1 answer

To arrange Diethyl ether, sec-Butyl alcohol, and pentane according to their expected boiling points, we need to consider the types of intermolecular forces present in each compound, as these forces largely determine boiling points.

  1. Pentane (C5H12): Pentane is an alkane and primarily exhibits London dispersion forces (induced dipole-induced dipole interactions). These forces are relatively weak compared to other types of intermolecular forces. Pentane has a boiling point of approximately 36 °C (97 °F).

  2. Diethyl ether (C4H10O): Diethyl ether is an organic compound that can engage in dipole-dipole interactions due to its ether functional group, as well as hydrogen bonding with water due to its oxygen atom. The boiling point of diethyl ether is about 34.6 °C (94.3 °F). Although it has some stronger dipole-dipole interactions compared to pentane, it is slightly lower in boiling point because ethers have a relatively small molecular weight and their weak hydrogen bonding does not significantly elevate the boiling point compared to alcohols.

  3. Sec-Butyl alcohol (C4H10O): Sec-butyl alcohol (or 2-butanol) has a hydroxyl (-OH) group that can form hydrogen bonds, which are significantly stronger than the dipole-dipole interactions in diethyl ether and the dispersion forces in pentane. As a result, sec-butyl alcohol has a higher boiling point, roughly around 99.5 °C (211 °F).

Based on this reasoning, the expected order of boiling points from lowest to highest is:

  1. Pentane (lowest boiling point)
  2. Diethyl ether
  3. Sec-butyl alcohol (highest boiling point)

This order reflects the increasing strength of intermolecular forces present in each compound, with hydrogen bonding in the alcohol resulting in the highest boiling point.