To find the common difference for each sequence, we will subtract the previous term from the current term.
For the first sequence:
1052 - 1049 = 3
1055 - 1052 = 3
1058 - 1055 = 3
So, the common difference is 3 for the first sequence.
For the second sequence:
-4 - (-15) = 11
7 - (-4) = 11
18 - 7 = 11
So, the common difference is 11 for the second sequence.
The third sequence is given as a linear equation, y = 2x + 4, so there is no constant common difference.
Therefore, the sequence with the least common difference is the third sequence (y = 2x + 4), followed by the first sequence (common difference of 3), and finally the second sequence (common difference of 11).
Arranging them from least to greatest common difference:
-15, -4, 7, 18...
1049, 1052, 1055, 1058...
y=2x+4
Arrange the following from least to greatest common difference. (least on the bottom and highest on top)(1 point)
1049, 1052, 1055, 1058...
an=-3+ (n-1) 10
-15, -4, 7, 18...
y=2x+4
1 answer
1 answer