Question

Arrange the following from least to greatest common difference. (least on the bottom and highest on top)(1 point)

1049, 1052, 1055, 1058...

an=-3+ (n-1) 10

-15, -4, 7, 18...

y=2x+4

Answer 1

To find the common difference for each sequence, we will subtract the previous term from the current term.

For the first sequence:
1052 - 1049 = 3
1055 - 1052 = 3
1058 - 1055 = 3

So, the common difference is 3 for the first sequence.

For the second sequence:
-4 - (-15) = 11
7 - (-4) = 11
18 - 7 = 11

So, the common difference is 11 for the second sequence.

The third sequence is given as a linear equation, y = 2x + 4, so there is no constant common difference.

Therefore, the sequence with the least common difference is the third sequence (y = 2x + 4), followed by the first sequence (common difference of 3), and finally the second sequence (common difference of 11).

Arranging them from least to greatest common difference:

-15, -4, 7, 18...
1049, 1052, 1055, 1058...
y=2x+4