1. Apply equilibrium to the rock when it is submerged in water.
2. Solve the equation from step 1 for volume
1. Equilibrium:
{Force to hold rock stationary in water (apparent weight)}+ {Buoyant Force on rock} = {Weight of rock in air ¾}
V=1000N-609N/9810N/m^3=0.0399 m^3
V=39.9L
Arock weighs 1000N in air and 609N in water.Find its volume.
2 answers
1. Apply equilibrium to the rock when it is submerged in water.
2. Solve the equation from step 1 for volume
1. Equilibrium:
{Force to hold rock stationary in water (apparent weight)}+ {Buoyant Force on rock} = {Weight of rock in air}
V=1000N-609N/9810N/m^3=0.0399 m^3
V=39.9L
Sorry there is no 3/4
2. Solve the equation from step 1 for volume
1. Equilibrium:
{Force to hold rock stationary in water (apparent weight)}+ {Buoyant Force on rock} = {Weight of rock in air}
V=1000N-609N/9810N/m^3=0.0399 m^3
V=39.9L
Sorry there is no 3/4