Let's denote the number of pages Taylor read as \( x \).
According to the problem, Arlene read 30 pages, which is 10 pages more than half of the pages Taylor read. We can express this relationship mathematically.
First, half of the pages Taylor read is \(\frac{x}{2}\). Since Arlene read 10 pages more than this, we can write the equation as:
\[ \frac{x}{2} + 10 = 30 \]
To put this equation in the form \( px + q = r \), we can start by simplifying.
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Subtract 10 from both sides: \[ \frac{x}{2} = 20 \]
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Multiply both sides by 2 to eliminate the fraction: \[ x = 40 \]
Now rewrite the original equation in the required form \( px + q = r \):
From the equation \(\frac{x}{2} + 10 = 30\):
If we multiply through by 2 to eliminate the fraction: \[ x + 20 = 60 \]
In the \( px + q = r \) form, this can be expressed as: \[ 1x + 20 = 60 \]
So, the values of \( p \), \( q \), and \( r \) are:
- \( p = 1 \)
- \( q = 20 \)
- \( r = 60 \)
Thus, the equation representing this problem is: \[ x + 20 = 60 \]
And Taylor read \( 40 \) pages.