Ag 2 = 2*107.87 = 215.74 grams / mol of Ag2S
S = 32.06 grams / mol of Ag2S
so
Ag2S = 247.8 grams / mol ofAg2S
so yes
Argentite (Ag2S) is one of the common ores of silver. If 88.1 grams of sulfur was removed from ore, how many grams of Ag2S were mined to get pure silver?
_________ g Ag2S. Do NOT enter the unit and report your final answer with 4 SFs.
THIS IS WHAT I PUT.. is this correct? someone please let me know!
and thank you!
88.1 g S x (247.8gmol/ 32.065) = 680.84
3 answers
Thank you so much!
You are welcome.