To find the sum of the two diagonals of a rhombus, we first need to find the lengths of the two diagonals.
Let the shorter diagonal be x cm. Therefore, the longer diagonal will be 3x cm.
The area of a rhombus is given by the formula:
Area = (1/2) * d1 * d2
where d1 and d2 are the lengths of the diagonals.
Given that the area of the rhombus is 24 cm², we can substitute the values into the formula:
24 = (1/2) * x * 3x
24 = (3/2) * x²
x² = 16
x = 4 cm
Therefore, the shorter diagonal is 4 cm and the longer diagonal is 3 * 4 = 12 cm.
The sum of the two diagonals is:
4 + 12 = 16 cm
So, the sum of the two diagonals of the rhombus is 16 cm.
Area of rhombus is 24cm² and one of the diagonal is triple the other in length find the sum of the two diagonals
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