Area of Non right Triangles Practice

Answer 1

1. Find the area of a triangle with side lengths of 6, 8, and 10.

To find the area of a triangle with side lengths of 6, 8, and 10, we can use the Heron's formula:

s = (a + b + c) / 2

Where a, b, and c are the side lengths of the triangle.

In this case, a = 6, b = 8, and c = 10.

s = (6 + 8 + 10) / 2
s = 24 / 2
s = 12

Now we can use Heron's formula to find the area of the triangle:

Area = √[s(s-a)(s-b)(s-c)]
Area = √[12(12-6)(12-8)(12-10)]
Area = √[12*6*4*2]
Area = √[576]
Area ≈ 24

Therefore, the area of the triangle with side lengths of 6, 8, and 10 is approximately 24 square units.

2. Find the area of a triangle with a base of 5 units and a height of 9 units.

To find the area of a triangle with a base of 5 units and a height of 9 units, we can use the formula for the area of a triangle:

Area = 1/2 * base * height
Area = 1/2 * 5 * 9
Area = 1/2 * 45
Area = 22.5

Therefore, the area of the triangle with a base of 5 units and a height of 9 units is 22.5 square units.