To find the area of the composite figure described in the problem, let's break it down step by step.
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Identify the shape of the figure: The figure can be visualized as a large rectangle (main part) from which a smaller rectangle (the missing piece) is removed from the center left side.
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Dimensions of the large rectangle:
- The top side is 6 units.
- The bottom side is 6 units (so the top and bottom sides are equal).
- The right side is 8 units.
This indicates that the dimensions of the large rectangle are 6 units (width) and 8 units (height).
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Calculate the area of the large rectangle: \[ \text{Area}_{\text{large rectangle}} = \text{width} \times \text{height} = 6 \times 8 = 48 \text{ square units} \]
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Identify the dimensions of the missing rectangle:
- The vertical width of the missing rectangle on the left is 2 units from the top seen in the description.
- The height of the missing rectangle is represented as the remaining height of the large rectangle after the missing part, which appears to be (8 - 2) = 6 units.
Therefore, it seems that the missing rectangle has dimensions of 2 units (width) by 6 units (height).
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Calculate the area of the missing rectangle: \[ \text{Area}_{\text{missing rectangle}} = \text{width} \times \text{height} = 2 \times 6 = 12 \text{ square units} \]
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Calculate the area of the composite figure: To find the area of the figure, we will subtract the area of the missing rectangle from the area of the large rectangle: \[ \text{Area}{\text{figure}} = \text{Area}{\text{large rectangle}} - \text{Area}_{\text{missing rectangle}} = 48 - 12 = 36 \text{ square units} \]
Given this calculation, the area of the figure is 36 square units.
Final answer: 36 square units.