Are you annoyed with spam e-mail? Suppose a random sample of 200 Kent State students was asked this question of which 80% said that they are annoyed. From the provided information we can find the following:

Question

sample percent = 80% (sample proportion = .80)
standard deviation (S.D.) = .03

a. Set up the calculation of a 95% confidence interval to estimate the population proportion of Penn State students who are annoyed by spam e-mail?

.8 ± .06 =(.50 to .56) or (50 to 56) %
I think this is totally wrong -- help!