I can't interpret your answers.
1.
2x-y=4, or
y = 2x-4
has slope 2. So, the line through (3,2) with slope=2 is
y-2 = 2(x-3)
y = 2x-4
2.
y = 5/2 x + 3
has slope 5/2
so, the perpendicular line has slope -2/5
y+1 = -2/5 (x+1)
y = -2/5 x - 7/5
I'd be interested to know what steps you followed to arrive at your answers.
Are these Correct?
Write an equation for the line in point/slope form and slope/intercept form that has the given condition.
1. Passes through (3, 2) and is parallel to 2x-y=4
= 4x+y
2. Passes through (-1, -1) and is perpendicular to y = 5/2x + 3
=6\7x-2
1 answer
1 answer