Are my answers right? If they are wrong you don't have to tell me how to do it its okay =)

Question

A particle starts at time t=0 and moves along the x-axis so that its position at any time t(greater or equal to) 0 is given by x(t)=(t-1)^3 (2t-3)

1.find the velocity of the particle at any time t(greater or equal to) 0
2.for what values of t is the velocity of the particle less than zero?
3.find the value of t when the particle is moving and the acceleration is zero

My Answers:
1.(6t-9)(t-1)^2 + 2(t-1)^3
2.t(less than or equal to) 1
3.t=1

Answer 1

P1=(-3,2);P2=(-6,-2)