2KOH + H2SO4 ==>2H2O + K2SO4
2K^+(aq) + 2OH^-(aq) + 2H^+(aq) + SO4^-2(aq) ==> 2H2O(l) + 2K^+(aq) + SO4^-2(aq)
The net ionic equation is
2OH^-(aq) + 2H^+(aq) ==> 2H2O(l)
Then I would divide by 2 to give simply
OH^-(aq) + H^+(aq) --> H2O(l) but your prof may frown on not putting the coefficients there.
Aqueous sulfuric acid is neutralized by aqueous potassium hydroxide.
Express your answer as an ionic equation. Identify all of the phases in your answer.
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