6 sin 2x − 8 cos x + 9 sin x = 6
12sinxcosx - 8cosx + 9sinx - 6 = 0
4cosx(3sinx - 2) + 3(3sinx - 2) = 0
(3sinx - 2)(4cosx + 3) = 0
sinx = 2/3 OR cosx = -3/4, the last one is not possible
sinx = 2/3
x = .7297..
which matches b)
Make sure your calculator is set to radians for these type of questions, unless the question specifies degrees.
Approximate the solutions (to three decimal places) of the given equation in
the interval
(- pi/2, pi/2)
6 sin 2x − 8 cos x + 9 sin x = 6
Can you help with this please? I am studying for my Pre Calculus 1 exam and am stuck on this question...!
The answer options are
a. x = 0.398
b. x = 0.094
c. x = 0.139
d. x = 0.730
e. x = 1.336
1 answer