Approximate square root of 103, put in decimal form rounded to the nearest hundredth

1 answer

To approximate the square root of 103, we can start by estimating between the squares of two whole numbers.

We know that:

  • \(10^2 = 100\)
  • \(11^2 = 121\)

Since \(103\) is between \(100\) and \(121\), we know that:

\[ 10 < \sqrt{103} < 11 \]

Next, we can get closer by testing values between 10 and 11.

Calculating a few decimal values, we find:

  • \(10.1^2 = 102.01\)
  • \(10.2^2 = 104.04\)

Since \(102.01 < 103 < 104.04\), we know:

\[ 10.1 < \sqrt{103} < 10.2 \]

Let's narrow it down further:

  • \(10.15^2 = 103.0225\)

Since \(103.0225 > 103\), we also know:

\[ 10.1 < \sqrt{103} < 10.15 \]

Next, let's test \(10.14\):

  • \(10.14^2 = 102.8196\)

Since \(102.8196 < 103\), we have:

\[ 10.14 < \sqrt{103} < 10.15 \]

Thus, we can approximate \(\sqrt{103} \approx 10.14\).

Now, rounding to the nearest hundredth gives us:

\[ \sqrt{103} \approx 10.14 \]