To approximate 1935√, we can use the sequence of values 5-√, 5.2-√, 5.24-√, 5.249-√, 5.2499-√, etc.
By evaluating each value in the sequence, we can find that:
5-√ ≈ 2.236
5.2-√ ≈ 2.274
5.24-√ ≈ 2.278
5.249-√ ≈ 2.278
5.2499-√ ≈ 2.278
Therefore, 1935√ is approximately 2.278, correct to one decimal place.
Approximate 1935√
, correct to one decimal place, by using a sequence of values that gets closer and closer to 5–√
.(1 point)
1 answer
1 answer