The linear acceleration and the centripetal acceleration are perpendicular to each other so the magnitude is the square root of the sum of the squares.
linear
al = change in velocity/time
=[(53-125)km/h * 1000m/km /3600s/h] /12s
ac = v^2/r = [53/3.6]^2/15
then a = sqrt(al^2+ac^2)
Approaching one of the many sharp horizontal turns in the Monaco Grand Prix, an experienced Formula-1 driver slows down from 125 km/h to 53.0 km/h while rounding the bend in 12.0 s. If the driver continues to decelerate at this same rate and the radius of the curve is 15.0 m, what is the acceleration of the car the moment that its speed reaches 53.0 km/h? (Enter the magnitude.)
m/s2
2 answers
14.5m/s^2