Apply to zero power roll to create an equivalent expression to nine times in parentheses -33 power of 0+3 over two and parentheses 8-27 power of zero so we need the answer for that equation

Answer 1

To solve the expression \( 9 \times \left(-33^0 + \frac{3}{2}\right) \times (8 - 27^0) \), we first need to evaluate the components step by step.

1. Calculate \( -33^0 \): Any non-zero number raised to the power of 0 is 1. Therefore, \[ -33^0 = -1 \]

2. Calculate \( 27^0 \): Similarly, \[ 27^0 = 1 \]

3. Now substitute these values back into the expression: \[ 9 \times \left(-1 + \frac{3}{2}\right) \times (8 - 1) \]

4. Calculate \( -1 + \frac{3}{2} \): To combine these, convert -1 to a fraction: \[ -1 = -\frac{2}{2} \quad \text{so} \quad -1 + \frac{3}{2} = -\frac{2}{2} + \frac{3}{2} = \frac{1}{2} \]

5. Now calculate \( 8 - 1 \): \[ 8 - 1 = 7 \]

6. Substitute these results back into the expression: \[ 9 \times \frac{1}{2} \times 7 \]

7. Now perform the calculations:

   • First, calculate \( 9 \times \frac{1}{2} = \frac{9}{2} \).
   • Then, calculate \( \frac{9}{2} \times 7 = \frac{9 \times 7}{2} = \frac{63}{2} \).

Thus, the final result of the expression is: \[ \frac{63}{2} \]

That's the equivalent expression and final answer.