To apply the Zero Power Rule, we need to recall that any non-zero number raised to the power of zero is equal to one. Therefore, for any \( a \neq 0 \), we have:
\[ a^0 = 1 \]
Applying this rule to the expression \( 9 \cdot (-33)^0 + 32(8 - 27^0) \):
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Calculate \( (-33)^0 \): \[ (-33)^0 = 1 \]
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Calculate \( 27^0 \): \[ 27^0 = 1 \]
Now substitute these results back into the original expression:
\[ 9 \cdot 1 + 32(8 - 1) \]
This simplifies to:
\[ 9 + 32(8 - 1) \]
Now simplify further:
\[ 8 - 1 = 7 \]
So the expression becomes:
\[ 9 + 32 \cdot 7 \]
If we calculate \( 32 \cdot 7 \):
\[ 32 \cdot 7 = 224 \]
Finally, add \( 9 \) and \( 224 \):
\[ 9 + 224 = 233 \]
Thus, the final simplified expression is:
\[ 233 \]
Therefore, if we present the equivalent parts of the original expression, we can write:
\[ 9 \cdot (-33)^0 + 32(8 - 27^0) = 9 \cdot 1 + 32(8 - 1) \]
Which is:
\[ = 9 + 32(7) \]
So your complete equivalent expression with the evaluated components is:
9 ⋅ 1 + 32 (8 - 1) = 9 + 32 (7)