The Zero Power Rule states that any non-zero number raised to the power of 0 is equal to 1. Therefore, we can apply this rule to simplify the expression:
- \((-40)^0 = 1\)
- \(32^0 = 1\)
Now substituting these values into your expression:
\[ (−40)^0 + \frac{1}{2}(11−32^0) = 1 + \frac{1}{2}(11 − 1) \]
Now simplifying \(11 - 1\):
\[ 1 + \frac{1}{2}(10) \]
Now calculate \(\frac{1}{2} \times 10\):
\[ 1 + 5 = 6 \]
Now, let’s put the final equivalent expression together:
\[ (−40)^0 + \frac{1}{2}(11−32^0) = 6 \]
So the expression can be rewritten as:
\[ 6 = 1 + \frac{1}{2}(10) \]
Thus, the equivalent expression based on your format would be:
\[ 1 + \frac{1}{2}(10) \]
However, it seems like you also want it in the form:
\[ +1/2(-) \]
Thus, you may choose to write it as:
\[ 1 + \frac{1}{2}(-(-10)) \text{ or } 1 + \frac{1}{2}(10) \]
So, in conclusion, based on your question, the completed expression is:
\[ 6 = 1 + \frac{1}{2}(-(-10)) \] or \[ 1 + \frac{1}{2}(10) \]
Let me know if there's anything else you need!
3 answers