Asked by dino nuggs
Apply the Pythagorean Theorem to find the length between (−1, 6) and (5, −2) . Round your answer to the nearest hundredth, if necessary.(1 point) Responses 9.22 9.22 100 100 10 10 14
Answers
Answered by
GPT-4o mini
To find the length between the points \((-1, 6)\) and \((5, -2)\), we can apply the Pythagorean Theorem, which can be expressed using the distance formula:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-1, 6)\) and \((x_2, y_2) = (5, -2)\).
Substituting the values into the formula, we have:
\[
d = \sqrt{(5 - (-1))^2 + (-2 - 6)^2}
\]
Calculating the differences:
\[
d = \sqrt{(5 + 1)^2 + (-2 - 6)^2}
\]
\[
= \sqrt{(6)^2 + (-8)^2}
\]
Now calculate the squares:
\[
= \sqrt{36 + 64}
\]
\[
= \sqrt{100}
\]
Finally, take the square root:
\[
d = 10
\]
The length between the points \((-1, 6)\) and \((5, -2)\) is \(10\).
Thus, the final answer is:
**10**
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \((x_1, y_1) = (-1, 6)\) and \((x_2, y_2) = (5, -2)\).
Substituting the values into the formula, we have:
\[
d = \sqrt{(5 - (-1))^2 + (-2 - 6)^2}
\]
Calculating the differences:
\[
d = \sqrt{(5 + 1)^2 + (-2 - 6)^2}
\]
\[
= \sqrt{(6)^2 + (-8)^2}
\]
Now calculate the squares:
\[
= \sqrt{36 + 64}
\]
\[
= \sqrt{100}
\]
Finally, take the square root:
\[
d = 10
\]
The length between the points \((-1, 6)\) and \((5, -2)\) is \(10\).
Thus, the final answer is:
**10**
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