To find the distance between two points using the Pythagorean Theorem, we can follow these steps:
1. Identify the coordinates of the two points: (-1, 6) and (5, -2).
2. Subtract the x-coordinates and the y-coordinates separately to find the differences between the two points:
Δx = x2 - x1 = 5 - (-1) = 6
Δy = y2 - y1 = -2 - 6 = -8
3. Plug the differences into the Pythagorean Theorem formula, which states that the square of the hypotenuse (distance) is equal to the sum of the squares of the other two sides:
c^2 = Δx^2 + Δy^2
c^2 = 6^2 + (-8)^2
c^2 = 36 + 64
c^2 = 100
4. Take the square root of both sides to find the length of the hypotenuse (distance):
c = √100
c = 10
Therefore, the length between (-1, 6) and (5, -2) is 10 units. The correct answer is 10.
Apply the Pythagorean Theorem to find the length between (−1, 6) and (5, −2) . Round your answer to the nearest hundredth, if necessary.(1 point)
Responses
9.22
9.22
14
14
10
10
100
100
9 answers
are you sure?
Apologies for the confusion. I made a mistake in my previous response.
To find the distance between the points (-1, 6) and (5, -2) using the Pythagorean Theorem, follow these steps:
1. Identify the coordinates of the two points: (-1, 6) and (5, -2).
2. Subtract the x-coordinates and y-coordinates separately to find the differences between the two points:
Δx = x2 - x1 = 5 - (-1) = 6
Δy = y2 - y1 = -2 - 6 = -8
3. Use the differences to find the length (distance) using the Pythagorean Theorem:
c^2 = Δx^2 + Δy^2
c^2 = 6^2 + (-8)^2
c^2 = 36 + 64
c^2 = 100
4. Take the square root of both sides to find the length of the hypotenuse (distance):
c = √100
c = 10
Therefore, the length between (-1, 6) and (5, -2) is 10 units. The correct answer is 10. I apologize for the confusion in my previous response.
To find the distance between the points (-1, 6) and (5, -2) using the Pythagorean Theorem, follow these steps:
1. Identify the coordinates of the two points: (-1, 6) and (5, -2).
2. Subtract the x-coordinates and y-coordinates separately to find the differences between the two points:
Δx = x2 - x1 = 5 - (-1) = 6
Δy = y2 - y1 = -2 - 6 = -8
3. Use the differences to find the length (distance) using the Pythagorean Theorem:
c^2 = Δx^2 + Δy^2
c^2 = 6^2 + (-8)^2
c^2 = 36 + 64
c^2 = 100
4. Take the square root of both sides to find the length of the hypotenuse (distance):
c = √100
c = 10
Therefore, the length between (-1, 6) and (5, -2) is 10 units. The correct answer is 10. I apologize for the confusion in my previous response.
Could you explain why 9.22 is incorrect?
Apologies for the confusion.
To find the distance between the points (-1, 6) and (5, -2) using the Pythagorean Theorem, we can follow these steps:
1. Identify the coordinates of the two points: (-1, 6) and (5, -2).
2. Subtract the x-coordinates and y-coordinates separately to find the differences between the two points:
Δx = x2 - x1 = 5 - (-1) = 6
Δy = y2 - y1 = -2 - 6 = -8
3. Use the differences to find the length (distance) using the Pythagorean Theorem:
c^2 = Δx^2 + Δy^2
c^2 = 6^2 + (-8)^2
c^2 = 36 + 64
c^2 = 100
4. Take the square root of both sides to find the length of the hypotenuse (distance):
c = √100
c = 10
The correct answer is 10 units, not 9.22. I apologize for any confusion caused.
To find the distance between the points (-1, 6) and (5, -2) using the Pythagorean Theorem, we can follow these steps:
1. Identify the coordinates of the two points: (-1, 6) and (5, -2).
2. Subtract the x-coordinates and y-coordinates separately to find the differences between the two points:
Δx = x2 - x1 = 5 - (-1) = 6
Δy = y2 - y1 = -2 - 6 = -8
3. Use the differences to find the length (distance) using the Pythagorean Theorem:
c^2 = Δx^2 + Δy^2
c^2 = 6^2 + (-8)^2
c^2 = 36 + 64
c^2 = 100
4. Take the square root of both sides to find the length of the hypotenuse (distance):
c = √100
c = 10
The correct answer is 10 units, not 9.22. I apologize for any confusion caused.
Use the image to answer the question.
A graph shows quadrant 1 with the x-axis and y-axis ranging from 0 to positive 5. Data points marked are point A at left parenthesis 1 comma 2 right parenthesis, point B at left parenthesis 3 comma 2 right parenthesis, point C at left parenthesis 3 comma 4 right parenthesis, and point D at left parenthesis 1 comma 4 right parenthesis. A line joins points A to B, B to C, C to D, and D to A, forming a rectangle.
Apply the Pythagorean Theorem to find the length of the diagonal of the square. Round your answer to the nearest hundredth, if necessary.
(1 point)
Responses
8
8
4.24
4.24
2.83
2.83
4
4
Skip to navigation
page 8 of
A graph shows quadrant 1 with the x-axis and y-axis ranging from 0 to positive 5. Data points marked are point A at left parenthesis 1 comma 2 right parenthesis, point B at left parenthesis 3 comma 2 right parenthesis, point C at left parenthesis 3 comma 4 right parenthesis, and point D at left parenthesis 1 comma 4 right parenthesis. A line joins points A to B, B to C, C to D, and D to A, forming a rectangle.
Apply the Pythagorean Theorem to find the length of the diagonal of the square. Round your answer to the nearest hundredth, if necessary.
(1 point)
Responses
8
8
4.24
4.24
2.83
2.83
4
4
Skip to navigation
page 8 of
To find the length of the diagonal of the square formed by the points A(1, 2), B(3, 2), C(3, 4), and D(1, 4), we can use the Pythagorean Theorem.
The diagonal of a square forms a right triangle with two sides equal to the side length of the square.
1. Calculate the length of one side of the square:
The distance between A(1, 2) and B(3, 2) is 2 units.
The distance between B(3, 2) and C(3, 4) is 2 units.
Thus, the length of one side of the square is 2 units.
2. Use the length of one side of the square to find the length of the diagonal:
The diagonal forms a right triangle with two sides of length 2 units.
Applying the Pythagorean Theorem: c^2 = a^2 + b^2.
Here, a = 2 and b = 2.
c^2 = 2^2 + 2^2
c^2 = 4 + 4
c^2 = 8
c ≈ √8 ≈ 2.83 (rounded to the nearest hundredth)
Therefore, the length of the diagonal of the square formed by the given points is approximately 2.83 units. The correct answer is 2.83.
The diagonal of a square forms a right triangle with two sides equal to the side length of the square.
1. Calculate the length of one side of the square:
The distance between A(1, 2) and B(3, 2) is 2 units.
The distance between B(3, 2) and C(3, 4) is 2 units.
Thus, the length of one side of the square is 2 units.
2. Use the length of one side of the square to find the length of the diagonal:
The diagonal forms a right triangle with two sides of length 2 units.
Applying the Pythagorean Theorem: c^2 = a^2 + b^2.
Here, a = 2 and b = 2.
c^2 = 2^2 + 2^2
c^2 = 4 + 4
c^2 = 8
c ≈ √8 ≈ 2.83 (rounded to the nearest hundredth)
Therefore, the length of the diagonal of the square formed by the given points is approximately 2.83 units. The correct answer is 2.83.
Distance and the Pythagorean Theorem Quick Check answer
1. 2.83
2. 5.39
3. 10
4. 6:40
5. 8.54
100% correct.
Don't worry bot, you are not eligible to understand this.
1. 2.83
2. 5.39
3. 10
4. 6:40
5. 8.54
100% correct.
Don't worry bot, you are not eligible to understand this.
Thank you for providing the correct answers. I apologize for any confusion caused earlier. If you have any more questions or need further assistance, feel free to ask.