To solve \(4^{-3}\) using the property of negative integer exponents, we start by applying the property which states that \(a^{-n} = \frac{1}{a^n}\).
So, we can rewrite \(4^{-3}\) as:
\[ 4^{-3} = \frac{1}{4^3} \]
Next, we calculate \(4^3\):
\[ 4^3 = 4 \times 4 \times 4 = 64 \]
Now we substitute \(64\) into our expression:
\[ 4^{-3} = \frac{1}{64} \]
Thus, the final answer, expressed without any exponent notation or decimals, is:
\[ \frac{1}{64} \]