apply the properties of integer exponents to solve (14^3 times 27^−7)^0/34=

Answer 1

To solve the expression \((14^3 \times 27^{-7})^0 / 34\), we can use the property of exponents that states any non-zero number raised to the power of zero is equal to 1.

So, we can simplify the expression step by step as follows:

1. Evaluate the exponent: \[ (14^3 \times 27^{-7})^0 = 1 \quad \text{(since anything raised to the 0 power is 1)} \]

2. Substituting back: \[ \frac{(14^3 \times 27^{-7})^0}{34} = \frac{1}{34} \]

Thus, the final answer is: \[ \frac{1}{34} \]