Apply the properties of integer exponents to simplify the algebraic expression (−5a3b4c−23a−4b0c3)−2 .(1 point)

Responses

c10a14b8
Start Fraction c superscript 10 baseline over a superscript 14 baseline b superscript 8 baseline End Fraction

−5c103a14b8
Start Fraction negative 5 c superscript 10 baseline over 3 a superscript 14 baseline b superscript 8 baseline End Fraction

925a12
Start Fraction 9 over 25 a superscript 12 baseline End Fraction

9c1025a14b8

1 answer

To simplify the expression \((−5a^3b^4c−23a^{-4}b^0c^3)^{-2}\), we will follow the properties of integer exponents step by step.

  1. Simplify inside the parentheses: \(-5a^3b^4c - 23a^{-4}b^0c^3\)

    • Since \(b^0 = 1\), the second term simplifies to \(-23a^{-4}c^3\).
    • Thus, we have:
      \(-5a^3b^4c - 23a^{-4}c^3\).
  2. Combine the terms:
    The expression cannot be simplified further as-is since they have different variable powers. So we keep it as it is.

  3. Raise the whole expression to the power of -2:
    \((−5a^3b^4c - 23a^{-4}c^3)^{-2}\).

  4. Distributing the negative exponent:
    When raising an expression to a negative power, we take the reciprocal of the expression and change the sign of the exponent: \[\frac{1}{(-5a^3b^4c - 23a^{-4}c^3)^{2}}\]

  5. Consider the expression in the denominator:
    To further analyze:

    • Simplify terms if applicable by factoring out common bases if possible.
    • However, as given, this expression remains complex.
  6. Analyzing the terms:
    But for simplifying specific terms after expanding, we will expand \((-5a^3b^4c)\) and \(-23a^{-4}c^3\) if writings appear quadratic: We can calculate:

    • \((-5a^3b^4c)^2\) gives \(25a^6b^8c^2\).
    • \((-23a^{-4}c^3)^2\) gives \(529a^{-8}c^6\).
  7. Adding or handling the distribution of squares gives: Hence \(= 25a^6b^8c^2 + 529a^{-8}c^6\).

  8. Final result:
    Therefore, the whole expression raised will give: \[\frac{1}{25a^6b^8c^2 + 529a^{-8}c^6}\] retain the basic structure on final returns.

However, among the response choices given, the closest to any manipulation returning the values in certain forms would rotate back down as common-base separation designed.

Thus the correct answer among your options would be:

c10a14b8 \[ \frac{c^{10}}{a^{14}b^{8}} \]

Please confirm if further simplifications can clear or should analyze another route of base handling if needed!