To solve the expression \((5^{-3})^6 \times \frac{5^{17}}{10^{-2}}\) using the properties of integer exponents, we will follow these steps:
- Apply the exponent rule \((a^m)^n = a^{mn}\) to simplify \((5^{-3})^6\).
- Simplify the fraction \(\frac{5^{17}}{10^{-2}}\).
- Combine the results and simplify further.
Step 1: Simplify \((5^{-3})^6\)
Using the exponent rule \((a^m)^n = a^{mn}\):
\[ (5^{-3})^6 = 5^{-18} \]
Step 2: Simplify \(\frac{5^{17}}{10^{-2}}\)
Recall that \(10^{n} = 2^{n} \cdot 5^{n}\). Therefore, we can rewrite \(10^{-2}\) as:
\[ 10^{-2} = \frac{1}{10^2} = \frac{1}{2^2 \cdot 5^2} = \frac{1}{4 \cdot 25} = \frac{1}{100} \]
Hence,
\[ \frac{5^{17}}{10^{-2}} = 5^{17} \cdot 10^2 = 5^{17} \cdot 100 = 5^{17} \cdot (10^2) = 5^{17} \cdot (2^2 \cdot 5^2) = 5^{17} \cdot 2^2 \cdot 5^2 \]
This further simplifies to:
\[ 5^{17} \cdot 4 \cdot 5^2 = 4 \cdot 5^{17 + 2} = 4 \cdot 5^{19} \]
Step 3: Combine Results
Now we can combine \(5^{-18}\) and \(4 \cdot 5^{19}\):
\[ 5^{-18} \cdot (4 \cdot 5^{19}) = 4 \cdot 5^{-18 + 19} = 4 \cdot 5^{1} \]
Step 4: Rewrite with Positive Exponents
Since \(5^1 = 5\), we have:
\[ 4 \cdot 5 = 20 \]
Thus, the final equivalent expression with only positive exponents is:
\[ \boxed{20} \]