To simplify the expression \((4r^4y^{-4})^3/(z^7y^3)^2\), we will apply the properties of integer exponents step by step.
-
Expand the Numerator and Denominator:
First, apply the exponent to both the numerator and denominator:
\[ (4r^4y^{-4})^3 = 4^3(r^4)^3(y^{-4})^3 \] \[ (z^7y^3)^2 = (z^7)^2(y^3)^2 \]
-
Calculate Each Part:
Now, we calculate each of those parts:
-
For the numerator: \[ 4^3 = 64 \] \[ (r^4)^3 = r^{4 \cdot 3} = r^{12} \] \[ (y^{-4})^3 = y^{-4 \cdot 3} = y^{-12} \]
Thus, the numerator simplifies to: \[ 64r^{12}y^{-12} \]
-
For the denominator: \[ (z^7)^2 = z^{7 \cdot 2} = z^{14} \] \[ (y^3)^2 = y^{3 \cdot 2} = y^6 \]
Thus, the denominator simplifies to: \[ z^{14}y^6 \]
-
-
Combine the Results:
Now, we have the expression: \[ \frac{64r^{12}y^{-12}}{z^{14}y^6} \]
-
Simplify:
When dividing powers of the same base, we subtract the exponents: \[ y^{-12 - 6} = y^{-18} \]
So the expression becomes: \[ \frac{64r^{12}}{z^{14}y^{18}} \]
-
Final Expression:
Therefore, the simplified equivalent algebraic expression is: \[ \frac{64r^{12}}{z^{14}y^{18}} \]
This is the final result for the given expression using the properties of integer exponents.