Apply the Fundamental Theorem of Algebra to find the number of roots for the polynomial x3+x2−16x−16=0

1 answer

The Fundamental Theorem of Algebra states that a polynomial of degree \( n \) has exactly \( n \) roots in the complex number system (counting multiplicities).

In the given polynomial:

\[ x^3 + x^2 - 16x - 16 = 0 \]

the degree of the polynomial is 3 (since the highest power of \( x \) is 3).

According to the Fundamental Theorem of Algebra, this polynomial will have exactly 3 roots in the complex number system. These roots may be real or complex, and they can include repeated roots, but there will be a total of 3 roots when counted with their multiplicities.

So, the number of roots for the polynomial \( x^3 + x^2 - 16x - 16 = 0 \) is:

\[ \boxed{3} \]