Apply the Fundamental Theorem of Algebra to find the number of roots for the equation

12x-6x^2+3x^4=6x^3+2x-x^4


.

A
0

B
1

C
2

D
3

E
4

1 answer

To apply the Fundamental Theorem of Algebra to the equation

\[ 12x - 6x^2 + 3x^4 = 6x^3 + 2x - x^4, \]

we first need to rearrange the equation into standard polynomial form by moving all terms to one side of the equation:

\[ 3x^4 + x^4 - 6x^3 - 6x^2 + 12x - 2x = 0. \]

Combining like terms gives:

\[ 4x^4 - 6x^3 - 6x^2 + 10x = 0. \]

Now we can factor out the greatest common factor, which is 2:

\[ 2(2x^4 - 3x^3 - 3x^2 + 5x) = 0. \]

From here, we can determine the number of roots by analyzing the polynomial \( 2x^4 - 3x^3 - 3x^2 + 5x \).

The degree of the polynomial \( 2x^4 - 3x^3 - 3x^2 + 5x \) is 4. According to the Fundamental Theorem of Algebra, a polynomial of degree \( n \) has exactly \( n \) roots in the complex number system (counting multiplicities).

Therefore, in this case, since the polynomial is of degree 4, we can conclude that it has:

4 roots.

Thus, the answer is:

E. 4