Apply the Distributive Property to show 3i[(2i)+(−3i−5)] in its simplest form.(1 point)

1 answer

To apply the Distributive Property to the expression \(3i[(2i) + (-3i - 5)]\), we first simplify the expression inside the brackets.

  1. Simplify the expression inside the brackets: \[ (2i) + (-3i - 5) = 2i - 3i - 5 = -i - 5 \]

  2. Rewrite the expression: \[ 3i[-i - 5] \]

  3. Apply the Distributive Property: \[ 3i \cdot (-i) + 3i \cdot (-5) \]

  4. Calculate each term:

    • For the first term: \[ 3i \cdot (-i) = -3i^2 \] Since \(i^2 = -1\), we have: \[ -3i^2 = -3(-1) = 3 \]

    • For the second term: \[ 3i \cdot (-5) = -15i \]

  5. Combine the results: \[ 3 - 15i \]

So, the expression \(3i[(2i) + (-3i - 5)]\) in its simplest form is: \[ \boxed{3 - 15i} \]