take the log of both sides:
3logx+1.5logy-.5logz=logk
Apply logarithms to create a linear relationship:
((x^3)(y^1.5))/(z^.5)=k
2 answers
3*log(x)+1.5log(y)-0.5log(z)=log(k)
((x^3)(y^1.5))/(z^.5)=k
2 answers