To solve the expression \((14^3 \cdot 27^{-7})^0 / 3^4\), let's apply the properties of exponents:
- Exponent Rule for Zero: Any non-zero expression raised to the power of zero is equal to 1. Therefore, \((14^3 \cdot 27^{-7})^0 = 1\).
Now the expression simplifies to:
\[ \frac{1}{3^4} \]
- Calculate \(3^4\):
\[ 3^4 = 3 \cdot 3 \cdot 3 \cdot 3 = 81 \]
So, we now have:
\[ \frac{1}{81} \]
Thus, the final simplified expression with no remaining exponents is:
\[ \frac{1}{81} \]